wsh_12 asked:
The Mariana trench is located in the Pacific Ocean at a depth of about 11500 m below the surface of the water. The density of seawater is 1025 kg/m^3.
If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle’s observation window (radius = 0.15 m)?
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P=P[atm]+pgh= (10^5)+(1025*9.8*11500)= 1.16*10^8 Pa
F=PA= 1.16*10^8*pi*(.15^2)= 8.19*10^6 N= 6.19 Mega N